5w^2+20w+20=0

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Solution for 5w^2+20w+20=0 equation: 



5w^2+20w+20=0

a = 5; b = 20; c = +20;
Δ = b2-4ac
Δ = 202-4·5·20
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-20}{10}=-2$

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